Why is the std. enthalpy change of formation for H2O (l) more
H2O Enthalpy Of Formation. Oh (g) → o (g) + h (g) δ r h°(0 k) = 4.4124.
Oh (g) → o (g) + h (g) δ r h°(0 k) = 4.4124.
Oh (g) → o (g) + h (g) δ r h°(0 k) = 4.4124. Oh (g) → o (g) + h (g) δ r h°(0 k) = 4.4124.
